| T O P I C R E V I E W |
| andrewdsto |
Posted - 07/16/2015 : 03:15:28 AM
Origin Ver. 2015 and Service Release sr2 (Select Help-->About Origin):
Operating System:Windows 7
Hi,
Just a short question on the rmod function. I dont think it is working as it should, see below.
rmod(6,2)=;
returns
rmod(6,2)=0
All ok, same the mod function. now
5*4.2=;
rmod(21,4.2)=;
we get
5*4.2=21
rmod(21,4.2)=4.2
however
rmod(21,5)=;
returns
rmod(21,5)=1
again ok
and
rmod(21,4.1)=;
returns
rmod(21,4.1)=0.5
again ok
its only when the remainder is meant to be zero we instead get the divisor.
interestingly if we run the folowing
4.2*6=;
25.2-(6*4.2)=;
we get
4.2*6=25.2
25.2-(6*4.2)=-3.5527136788005E-15
that is we do not get zero but instead a very small number.
I am thinking that where the modulus is zero, the rmod funtion infact returns not zero but a number that is very close to, but just below, the divisor which gets returned as the divisor. But this is only for real numbers and not integers.
just a thought.
thanks
Andrew |
| 1 L A T E S T R E P L I E S (Newest First) |
| SeanMao |
Posted - 07/16/2015 : 04:41:31 AM
Hi,
This is due to the rounding error, when you do rmod(21,4.2) you actually get remainder 4.199999... rather precise 0.
Regards!
Sean
OriginLab Tech. Service |
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