| T O P I C R E V I E W |
| goulven999 |
Posted - 03/01/2018 : 10:01:28 PM
Origin Ver. and Service Release: 9.0.0 (32bit)
Operating System: windows
My model use a complex equation and use the real part as y1 and the imaginary part as y2 for my fitting.
complex cc =Xadia+Xiso1/((1+(1i*2*pi*x*Tau1)^(1-Alpha1))^(Beta1));
y1 = cc.m_re;
y2 = -cc.m_im;
I can successfully fit a XYY dataset with the nlbeginr/nlfit/nlend
and obtain the fitting parameter.
My problem is to obtain the fitted curve.
Using the
fity=fit(fitx);
I can obtain the y1 value, and extract it to a new sheet, but I don't know how to obtain the y2 value.
Thank you
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| 2 L A T E S T R E P L I E S (Newest First) |
| goulven999 |
Posted - 03/05/2018 : 06:41:58 AM
Thanks for your help
I tried it but I get some error of range declaration.
I find an other solution:
first I generate the x value in a logarithm scale, then recalculate the imaginary and real part with the parameter obtain from the fitting. It work very well and I can control the lowest and highest X, as well as the number of point
csetvalue col:=Col(1) formula:=(10^((data(0, 1, 0.005))*7)/100);
csetvalue col:=col(2) formula:="imreal(Xadia+Xiso1/((1+(1i*2*pi*Col(1)*Tau1)^(1-Alpha1))^(Beta1))";
csetvalue col:=col(3) formula:="-imaginary(Xadia+Xiso1/((1+(1i*2*pi*Col(1)*Tau1)^(1-Alpha1))^(Beta1))";
Regards
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| yuki_wu |
Posted - 03/05/2018 : 02:52:15 AM
Hi,
You can get the fitted curve of y2 by specifying the index, for example:
fity2 = fit(fitx, 2);
Please refer to this example:
https://www.originlab.com/doc/LabTalk/ref/Fit-func
Hope it helps.
Regards,
Yuki
OriginLab
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