| T O P I C R E V I E W |
| Fulerena |
Posted - 07/03/2014 : 2:38:34 PM
Origin Ver. and Service Release (Select Help-->About Origin): 9.1 and 8.5
Operating System:Windows 7
Hi!!!
I have a problem. Sorry for the text but it's complicated to explain. I just survive programming in origin.
In my laboratory the program that gives us the data does not separate each cycle. A cycle is group of values between "x" up to "y" and return to "x". So many times. Some cycles.
Until now, x and y were constant in the cycles so I made a program which used the time as variable and it separated the cycles by ranges of increment of t. I calculated the time in the first cycle (0-t) between x-y-x and this was the first cycle, and for t-2t the second, etc.
wxt test:="col(A)[i]>=0 AND col(A)[i]<=24,75" iw:= [Book1]Sheet1 ow:=[C01]Sheet1;
My problem is, that now, the value of y change with cycles once has a value and in other cycle has a bigger one. So to reach greater potential increases the time between cycles and my program failed.
Someone would know me if you can program, for example, from the first value (line 1 in origin)to find the first maximum (line y) and copy a cycle in a column. And then the next value (line y+1) to the next maximum and then cutting and pasting cycle two in another column.
I know this is somewhat complicated to explain but if someone could help I'd appreciate it.
Thank you
|
| 1 L A T E S T R E P L I E S (Newest First) |
| greg |
Posted - 07/03/2014 : 4:41:42 PM
If I understand you, your x values increase to some value, then reset to a lower value and start increasing again and that represents a cycle?
If you want to break out each cycle XY pair, you can use this script:
// BEGIN SCRIPT
range rax = 1;
wo -a 2;
target = wks.ncols - 1;
wks.col$(target).type = 4;
mark1 = 1;
lastval = rax[1];
loop(ii,2,rax.GetSize())
{
val = rax[ii];
if( val < lastval )
{
mark2 = ii - 1;
wrcopy ow:=<input> c1:=1 c2:=2 r1:=mark1 r2:=mark2 dc1:=target dr1:=1 label:=LUC format:=1;
wo -a 2;
target = wks.ncols - 1;
wks.col$(target).type = 4;
mark1 = ii;
lastval = val;
}
else lastval = val;
}
// END SCRIPT
|
|
|
