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problem when working with vector & matrix

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[quote][i]Originally posted by Simon.N[/i]
[br]Origin Version (Select Help-->About Origin): 7 SR2
Operating System: vista

Hi,

This is the context :

I have two matrix of integers (mipower & midate).
I want to copy each row of them in different worksheet (ie having in each of the new worksheet, the nth row of mipower and the nth row of midate).

Unfortunately, the numbers i have at the end are not the one expected.

here is my code :

[code]for(jj=0; jj<iNbNommines; jj++)
	{
		//int iIndexCol = wks.AddCol(/*"candidat"*/);
		Worksheet feuille_resultats;
		feuille_resultats.Create();
		Column colDate = feuille_resultats.Columns(0);
		Column colPower = feuille_resultats.Columns(1);
		Dataset dsdate;
		dsdate.Attach(feuille_resultats, 0);
		Dataset dspower;
		dspower.Attach(feuille_resultats, 1);
		dsdate.SetSize(viNbEvent[jj]);
		dspower.SetSize(viNbEvent[jj]);
		
		
		for(int kk=0; kk<viNbEvent[jj]; kk++)
		{
			dspower[kk]=miNommineP[jj][kk];
			dsdate[kk]= dsTime[miNommineD[jj][kk]]; //here is a first problem since dsdate expects an integer whereas dsTime contains a date type (ex 03-07-2007 12:22:45).
			printf("right value: %d, left value : %d\n", miNommineP[jj][kk], dspower[kk]);
		}
	} [/code]

The resulting worksheet contains only '0' for the column dspower, and '-' for the column dsdate.

Besides, here is the trace of the printf line :
[code]
right value : 0,    left value : 0
right value : 0,    left value : 0
right value : 0,    left value : 0
right value : -97,    left value : 0
right value : 0,    left value : 0
right value : 0,    left value : 0
[/code]

Hope you'll can help me.

Thanks.

Simon Nicolas
[/quote]

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T O P I C R E V I E W
Simon.N	Posted - 07/03/2007 : 06:27:54 AM Origin Version (Select Help-->About Origin): 7 SR2 Operating System: vista Hi, This is the context : I have two matrix of integers (mipower & midate). I want to copy each row of them in different worksheet (ie having in each of the new worksheet, the nth row of mipower and the nth row of midate). Unfortunately, the numbers i have at the end are not the one expected. here is my code : for(jj=0; jj<iNbNommines; jj++) { //int iIndexCol = wks.AddCol(/"candidat"/); Worksheet feuille_resultats; feuille_resultats.Create(); Column colDate = feuille_resultats.Columns(0); Column colPower = feuille_resultats.Columns(1); Dataset dsdate; dsdate.Attach(feuille_resultats, 0); Dataset dspower; dspower.Attach(feuille_resultats, 1); dsdate.SetSize(viNbEvent[jj]); dspower.SetSize(viNbEvent[jj]); for(int kk=0; kk<viNbEvent[jj]; kk++) { dspower[kk]=miNommineP[jj][kk]; dsdate[kk]= dsTime[miNommineD[jj][kk]]; //here is a first problem since dsdate expects an integer whereas dsTime contains a date type (ex 03-07-2007 12:22:45). printf("right value: %d, left value : %d\n", miNommineP[jj][kk], dspower[kk]); } } The resulting worksheet contains only '0' for the column dspower, and '-' for the column dsdate. Besides, here is the trace of the printf line : right value : 0, left value : 0 right value : 0, left value : 0 right value : 0, left value : 0 right value : -97, left value : 0 right value : 0, left value : 0 right value : 0, left value : 0 Hope you'll can help me. Thanks. Simon Nicolas
1 L A T E S T R E P L I E S (Newest First)
Simon.N	Posted - 07/03/2007 : 10:17:18 AM I have modified the inner loop like this : for(int kk=0; kk<viNbEvent[jj]; kk++) { int tmp=miNommineP[jj][kk]; dspower[kk]=tmp; dsdate[kk]= dsTime[miNommineD[jj][kk]]; //here is a first problem since dsdate expects an integer whereas dsTime contains a date type (ex 03-07-2007 12:22:45). printf("right value: %d, left value : %d, tmp value\n", miNommineP[jj][kk], dspower[kk], tmp); } And now, the results are the same, but the printf command displays -1067958272 if right value is negative or 1079181312 if right value is positive. It seems to be the limits of an integer type.

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