| T O P I C R E V I E W |
| datrix |
Posted - 07/15/2009 : 7:20:14 PM
Hello,
itīs me again, with a probably easy question.
Can somebody help me with the right syntax to access the X / Y Labels
in a GraphLayer? I tried the part marked in red and other combinations.
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string CreateYLogScaleGraphObject(double x_beg, double x_end, double x_inc, string x_label, double y_beg, double y_end, string y_label){
GraphPage grphData;
grphData.Create("line.otp");
GraphLayer grphLayer = grphData.Layers();
Scale sc;
// X Scaling
sc = grphLayer.X;
sc.From = x_beg;
sc.To = x_end;
sc.Type = LINEAR_SPACE;
sc.Inc = x_inc;
grphLayer.LT_execute("lab -s -xb;", x_label);
// Y Scaling
sc = grphLayer.Y;
sc.From = y_beg;
sc.To = y_end;
sc.Type = LOG10_SPACE;
sc.Inc = 1;
grphLayer.LT_execute("layer.y.minorTicks = 8");
grphLayer.LT_execute("lab -s -yl;", y_label);
return grphData.GetName();
}
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Is it possible to access the labels with internal Origin Object Classes instead of LabTalk-Script commands?
Thanks,
datrix |
| 2 L A T E S T R E P L I E S (Newest First) |
| datrix |
Posted - 07/16/2009 : 05:35:20 AM
Exactly, what Iīve been looking for.
Works like a charm. ;)
Thanks from Germany.
datrix
|
| cpyang |
Posted - 07/15/2009 : 9:13:46 PM
The names of the XY titles are
XB = X bottom
YL = Y Left
XT = X Top
XR = X Right
You can then just access them by
grphLayer.GraphObjects("YL");
and use the .Text property to access the label, see
http://ocwiki.originlab.com/index.php?title=Category:GraphObject_%28class%29
CP
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