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 How to show dialog in XFBase::ExecuteLabTalk ?

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Alex-qwerty Posted - 01/25/2011 : 11:30:03 AM
OriginPro 8.1SR3 WinXP SP3
In help file of method XFBase::ExecuteLabTalk I found the phrase "The dialog can be opened, if so desired". How to force to show the dialog? I want to give for user a possibility to change some parameters of X-Function. When I use 
xf.ExecuteLabTalk(NULL, NULL);
xf is executed, but there is no dialog shown. How to show the dialog for user?
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Penn Posted - 01/25/2011 : 9:37:26 PM
Hi,

Maybe you have realized the prototype of this method:


int ExecuteLabTalk(LPCSTR lpcszArgs, vector<string>* pvsVarValues, 
    LPVOID lpRetData = NULL, int nRetDataXVT = XVT_INT, int* lpOCerr = NULL, 
    DWORD dwCntrl = 0, int nRecalculate = AU_NONE);

Argument DWORD dwCntrl can be set to LTXF_SHOW_DIALOG for opening the dialog. For example:

xf.ExecuteLabTalk(NULL, NULL, NULL, XVT_INT, NULL, LTXF_SHOW_DIALOG);


Penn

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