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 非线性PSO拟合尽管R2 0.99

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T O P I C    R E V I E W
yoyohami Posted - 03/25/2024 : 10:57:09 AM
Origin Ver. and Service Release (Select Help-->About Origin):
Operating System
大家好，PSO非线性方程使用的是：qt = qe^2*k2*t/1+qt*k2*t
我是新手小白，不太了解初始k2 qe的设置，因此我都选择了 k2=1, qe=1.
结果是拟合R2=0，99，
但是K2 = 4.15E33， 以及K2的标准误差SE= 6,16E44.

我无法知道问题在什么地方以及是否是因为我的数据点太少了而导致的？
我在这里附上我的原始数据 time(min) and qt(mg/g),希望能得到大家的指点。
非常感谢
Time (min) 0,0,120,120,1440,1440,10080, 10080
qe (mg/g) 0,0, 6.376 6.556 6.558 6.519 6.544 6.250

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