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Set Value and extracting numbers from strings

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[quote][i]Originally posted by evansti4[/i]
[br]Origin Ver. and Service Release (Select Help-->About Origin): 8.6
Operating System: XP

Hi,

I have a worksheet where the first column is a list of file names and I have been trying to use the set column value scripting area to take those file names and cut out the numbers in them and then put the numbers back together into a value. For example in column A I might have tth2p500.lvm and I would like to cut out the 2 and the 500 and put them back together in the next column as 2.500. Now I've been able to get it to work for a single number with

%a = %([Book]Worksheet,Column,Row)
%n = %[%a,>'p']
%n = %[%n,'.']
%m = %[%a,>'h']
%m = %[%m,'p']

and then in the formula area putting col(B) = %m + %n/1000.

I can't figure out how to assign %a so that it corresponds to whatever the file name is in that row not just the one I manually assign it by putting ([Book]Worksheet,1,1) for the first value. I would greatly appreciate any help.

-Tim

[/quote]

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T O P I C R E V I E W
evansti4	Posted - 05/11/2012 : 4:37:05 PM Origin Ver. and Service Release (Select Help-->About Origin): 8.6 Operating System: XP Hi, I have a worksheet where the first column is a list of file names and I have been trying to use the set column value scripting area to take those file names and cut out the numbers in them and then put the numbers back together into a value. For example in column A I might have tth2p500.lvm and I would like to cut out the 2 and the 500 and put them back together in the next column as 2.500. Now I've been able to get it to work for a single number with %a = %([Book]Worksheet,Column,Row) %n = %[%a,>'p'] %n = %[%n,'.'] %m = %[%a,>'h'] %m = %[%m,'p'] and then in the formula area putting col(B) = %m + %n/1000. I can't figure out how to assign %a so that it corresponds to whatever the file name is in that row not just the one I manually assign it by putting ([Book]Worksheet,1,1) for the first value. I would greatly appreciate any help. -Tim
4 L A T E S T R E P L I E S (Newest First)
Hideo Fujii	Posted - 05/14/2012 : 09:33:42 AM Hi evansti4, FYI, here is a list of string functions available in ver. 8.0(SR6) or later: http://wiki.originlab.com/~originla/ltwiki/index.php?title=Category:String_and_Characters_%28Labtalk%29 --Hideo Fujii OriginLab
evansti4	Posted - 05/11/2012 : 6:17:10 PM Thank you so much, Hideo that worked perfectly. And Easwar, that is much more readable. We just upgraded from 7 so I'll have to brush up on new notation and syntax. Thanks again, both of you.
easwar	Posted - 05/11/2012 : 6:08:56 PM Hi, Version 8.x has better string processing capability in script, and the code could be written the following way using new methods, and perhaps is more "readable" than the old % notation. Easwar OriginLab range rin=1, rout=2; string str$, str1$, str2$; for(int irow=1; irow<=rin.GetSize(); irow++) { str$=rin[irow]$; str1$=str.Between("h","p")$; str2$=str.Between("p",".")$; rout[irow]=%(str1$) + %(str2$)/1000; }
Hideo Fujii	Posted - 05/11/2012 : 4:57:55 PM Hi Tim, For ii-th row, the assignment %a=col(1)[ii]$; should work to set %a. Thus, maybe your code would look like: for(ii=1; ii<=wks.maxRows; ii++) { %a=col(1)[ii]$; %n = %[%a,>'p']; %n = %[%n,'.']; %m = %[%a,>'h']; %m = %[%m,'p']; col(B)[ii]= %m + %n/1000.; } --Hideo Fujii OriginLab

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