The Origin Forum
File Exchange
Try Origin for Free
The Origin Forum
Home | Profile | Register | Active Topics | Members | Search | FAQ | Send File to Tech support
 All Forums
 Origin Forum
 Origin Forum
 how to choose the row that I want ?

Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!

Screensize:
UserName:
Password:
Anti-Spam Code:
Format Mode:
Format: BoldItalicizedUnderlineStrikethrough Align LeftCenteredAlign Right Horizontal Rule Insert HyperlinkUpload FileInsert Image Insert CodeInsert QuoteInsert List
   
Message:

* HTML is OFF
* Forum Code is ON
Smilies
Smile [:)] Big Smile [:D] Cool [8D] Blush [:I]
Tongue [:P] Evil [):] Wink [;)] Clown [:o)]
Black Eye [B)] Eight Ball [8] Frown [:(] Shy [8)]
Shocked [:0] Angry [:(!] Dead [xx(] Sleepy [|)]
Kisses [:X] Approve [^] Disapprove [V] Question [?]

 
Check here to subscribe to this topic.
   

T O P I C    R E V I E W
nabilou Posted - 01/18/2013 : 10:33:14 AM
well my problem is the following:

I have 3 columns, A, B and C
A is X: x
B is Y: f(x)
Y is C: g(x)

knowing that f(x) depends on g(x) as follow:

f(x) = 1/Ln(g(x))
g(x) = [(f(x)/a)^(-1/2)]*b

I need to plot the two curves, but it was not easy because the two are not independent.

by cons, I thought of a solution to the problem. If I know the two initial values of f(x) and g(x), I can do it.

here's how:

A; B; C
1; b1=5; c1=3;
2; b2; c2;
3; b3; c3;
4; b4; c4;
5; b5; c5;

therefore, to calculate the value b2, I should use c1 = 3 , and to calculate the value c2 I should use b2. to calculate the value b3, I should use c2, and to calculate the value c3 I should use b3. and so on

the problem now is that I do not know how I do ...!
should I use set values ? C++ ? LabTalk ?


Thanks
2   L A T E S T    R E P L I E S    (Newest First)
nabilou Posted - 02/20/2013 : 05:01:59 AM
thank you, it's working..!

Thanks
Hideo Fujii Posted - 01/18/2013 : 1:44:10 PM
Hi nabilou,

Set Column Value tool wouldn't do your job because the computational process should proceed alternatively between col(B) and col(C), not independently.
Maybe you can try the script using a loop like following: 
lastRow=5;
col(A)=data(1,lastRow,1); //init=1, last=lastRow, inc=1
col(B)[1]=5;
col(C)[1]=3;
For(ii=2; ii<=lastRow; ii++) {
  col(B)[ii]=1/ln(col(C)[ii-1]);
  col(C)[ii]=((col(B)[ii]/col(A)[ii])^(-1/2))*col(B)[ii];
}

Hope this works as you expected.

--Hideo Fujii
OriginLab

The Origin Forum © 2020 Originlab Corporation Go To Top Of Page
Snitz Forums 2000