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 Nonlinear curve fitting with exponential function

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Thinh89 Posted - 08/09/2014 : 03:45:49 AM
Hi everybody
I am getting some confusions when i try to use nonlinear curve fitting with exponential function . I have tried in two ways , one is Origin and the other is in Excel to compare the result but it's not the same and the result in Excel looks like better than in Origin. Actually ,i use the diode equation : I = Is*exp(qV/n/k/T -1) so the expotential function should be y = a*exp(b*x)
Here is my result in both of them :


Thank for your helps
2   L A T E S T    R E P L I E S    (Newest First)
Thinh89 Posted - 08/11/2014 : 08:09:21 AM
Thank for your explaination . It should be very useful with someone who get the same problem with me but dont know why .
Have a good time !!!
cdrozdowski111 Posted - 08/09/2014 : 3:47:45 PM
Hey,

I was able to reproduce your results in Excel and Origin.

If you are concerned that the Origin results may not be quite right, try using another computational product to reproduce the fitting- for example Wolfram|Alpha (because it's easy to do online):

1) In your browser, navigate to http://http://www.wolframalpha.com/
2) Enter the below text (your data in the W|A required format) into the "Enter what you want to calculate or know about:" text box and click the "=" button.

exponential fit {0.24,1E-03},{0.34,0.005},{0.36,0.01},{0.39,0.02},{0.43,0.05},{0.46,0.1},{0.49,0.2},{0.53,0.5},{0.57,1},{0.6,2},{0.65,5.000},{0.68,10},{0.69,14}


You will see that Origin and W|A agree almost perfectly (as they should).

As per the following reference, Excel does a log transformation of the original Y data and then performs a linear fit of that data to get the fitting parameters for the original Y data. This produces somewhat incorrect results. Read the reference for a more thorough explanation.

http://www.mikemiddleton.com/Excel-Exponential-Curve-Fit-2010.pdf

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