All Forums  Origin Forum  Origin Forum  Help me global fit or independent fit?

Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!

Screensize: 640 x 480 800 x 600 1024 x 768 1280 x 1024 UserName: Password: Anti-Spam Code: Format Mode: Basic  Help  Prompt  Format: Font Andale Mono Arial Arial Black Book Antiqua Century Gothic Comic Sans MS Courier New Georgia Impact Lucida Console Script MT Bold Stencil Tahoma Times New Roman Trebuchet MS Verdana   Size 1 2 3 4 5 6   Color Black Red Yellow Pink Green Orange Purple Blue Beige Brown Teal Navy Maroon LimeGreen Message: * HTML is OFF * Forum Code is ON Smilies [quote][i]Originally posted by yusu135[/i] [br]Origin Ver. and Service Release (Select Help-->About Origin): Operating System: Hi I use this formula F(x)=(a*exp(-b*x))+(c*exp(-d*x)) the parameters a (0.5), b (-0.02), c (0.5) and d (0.5) I have selected Auto parameter initialization because I want the program calcule the parameters. My data is one X and twenty Y. I have 2 questions: where is the difference the global fit or independent fit? what is correct? I understand the independent fit analyze all curves for separate and global analyze all curves together. My output independent fit have: Reduced Chi-Sqr similar 0.005 in all curves Adj. R-Square similar 0.8 in all curves and une ANOVA for curve an the p value is significative. I don't understant the chi-sqr And ai Have this missage (1) Parameter Initialization was called. (2) Fitting No.1 Dataset ----------Levenberg-Marquardt----------- Reduced Chi-sqr = 0,00253824434968 COD(R^2) = 0,80269551337548 Iterations Performed = 11 Total Iterations in Session = 11 Fit converged. Chi-Sqr tolerance value of 1E-9 was reached. When I use Global fit I only have one ANOVA and the p value is 0, and the Reduced Chi-Sqr similar 0.003 in all curves and Adj. R-Square similar 0.8 I have this missage (4) ----------Levenberg-Marquardt----------- Reduced Chi-sqr = 0,00324618475966 COD(R^2) = 0,89876445796411 Iterations Performed = 17 Total Iterations in Session = 17 (5) Fit converged. Chi-Sqr tolerance value of 1E-9 was reached. where is the correct analisis I'm sorry for my explication and I don't know the people undetand my explication Thanks [/quote]   Check here to include your profile signature. Check here to subscribe to this topic.