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Screensize: 640 x 480 800 x 600 1024 x 768 1280 x 1024 UserName: Password: Anti-Spam Code: Format Mode: Basic  Help  Prompt  Format: Font Andale Mono Arial Arial Black Book Antiqua Century Gothic Comic Sans MS Courier New Georgia Impact Lucida Console Script MT Bold Stencil Tahoma Times New Roman Trebuchet MS Verdana   Size 1 2 3 4 5 6   Color Black Red Yellow Pink Green Orange Purple Blue Beige Brown Teal Navy Maroon LimeGreen Message: * HTML is OFF * Forum Code is ON Smilies [quote][i]Originally posted by ylibp[/i] [br]Dear Easwar I have tried to use a new method to solve my problem after getting your new suggestion. As you know, these are my original data listed below: X(x) B(Y) 0 0.45968 0.03067 0.45575 0.05205 0.45254 0.1 0.44414 0.17067 0.42936 0.34311 0.38642 0.58933 0.32282 1 0.24072 1.50133 0.18831 2.176 0.15892 2.62578 0.14516 3.26133 0.12791 3.89067 0.11652 4.42933 0.11048 5.13867 0.10211 5.992 0.09002 7.016 0.08361 7.784 0.07652 8.86133 0.06993 10 0.0638 I tried to get the expression of function y=f(x) for these data in order to get ratio=f(x/3)/f(x). Although we fit our data (in col B) by using y=p1+p2*x+p3*x^2+p4*x^3+p5*x^4+p6*x^5+p7*x^6+p8*x^7+p9*x^8+p10*x^9+p11*x^10 ...(1), a series of parameters p1 to p11 is not good enough. So according to the equation (1), I cannot get a reasonable Ration=f(x/3)/f(x). You suggestion is very good. I tried to use y=f(x)=nlsf.p1+nlsf.p2*col(x)+nlsf.p3*col(x)^2+nlsf.p4*col(x)^3+nlsf.p5*col(x)^4+nlsf.p6*col(x)^5+nlsf.p7*col(x)^6+nlsf.p8*col(x)^7+nlsf.p9*col(x)^8+nlsf.p10*col(x)^9+nlsf.p11*col(x)^10 ...(2) It is very close to my original data. Although I do not know what p1 to p11 are, I can get f(x/3). In order to get f(x/3), I change X(x) data by dividing 3. Then set the column as a new X(x). I still use equation (2) to calculate and get a new column which is f(x/3). Finally, I reach my purpose to get f(x/3)/f(x). Thank you again. Yang [/quote]   Check here to include your profile signature. Check here to subscribe to this topic.