| T O P I C R E V I E W |
| SkBible |
Posted - 11/20/2017 : 3:38:14 PM
Origin Ver. and Service Release (Select Help-->About Origin): OriginPro 2017
Operating System: Windows 10 64 Bit
I tried to plot z(x,y) = 0.5 + 0.01*(x^3)+0.02*(x)*(y^2) - 0.4*(x)*(y)*(1-(x+y)) + 0.03*y*(1-(x+y))^2
The range of each variable is between 0 and 1. [ 0 <= x <= 1, 0 <= y <= 1]
Thanks to OriginPro 2017, I got a decent 3D graph.
However, I am wondering if I can add the condition, 0 <= x + y <= 1.
If it is possible, how do I add this condition?
Within that specific region, 0 <= x <= 1, 0 <= y <= 1 and 0 <= x + y <= 1, I want to plot this formula.
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| 2 L A T E S T R E P L I E S (Newest First) |
| SkBible |
Posted - 11/20/2017 : 6:38:33 PM
Thank you!
I appreciate your help!
Sincerely,
Sungkyung Kim |
| snowli |
Posted - 11/20/2017 : 4:59:50 PM
Hello,
Origin supports conditional operator https://www.originlab.com/doc/LabTalk/guide/Operators#Conditional_Operator_.28.3F:.29
So in Function Plot dialog, enter this formula instead:
(x+y)<1?0.5 + 0.01*(x^3)+0.02*(x)*(y^2) - 0.4*(x)*(y)*(1-(x+y)) + 0.03*y*(1-(x+y))^2:
So if (x+y)<1, it will fill with the formula. If not, it will be filled with missing values. Note: no value or expression after : .
BTW, since your x and y both start from 0, i didn't enter (x+y)>0 in condition.
Thanks, Snow |
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