| T O P I C R E V I E W |
| AKazak |
Posted - 08/13/2021 : 05:39:00 AM
OriginPro 2022 (64-bit) Beta2 9.9.0.105
Windows 7 SP1 x64
Greetings!
What does this option work and how can I specify this for all point indices (https://www.originlab.com/doc/LabTalk/ref/Legend-Substitution-Notation#Plot_Symbol_Component)?
quote:
\L([LayerIndex.]PlotIndex[,PointIndex[,Option]])
1=Show Border or Edge color as a block, 2=Show Interior color as a block, 3=Show Pattern Color (or Black) as a block, 4=Show empty Symbol (or special Not Used), 5=Not Used, 6=Not Used, 7=Show actual style.
Thank you.
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Andrey |
| 5 L A T E S T R E P L I E S (Newest First) |
| snowli |
Posted - 08/13/2021 : 4:13:15 PM
Yes. Basically.
Thanks, Snow |
| AKazak |
Posted - 08/13/2021 : 12:17:19 PM
quote:
Originally posted by snowli
It depends what plot type it is.
E.g. try to plot scatter plot with open circle, border and fill use different colors.
Though it's scatter plot, u can use the following to show blocks instead of circle shape in legend.
\l(1,4,1) it will show a block with border color of 4th point
\l(1,4,2) it will show a block with fill color of 4th point
Try to plot a bar chart with each bar using different border color, fill color and pattern colors.
U can use the following
\(1,4,1) to show block with border color of 4th point
\(1,4,2) to show block with fill color of 4th point
\(1,4,3) to show block with pattern color of 4th point
\(1,4,4) will show open circle with black color no matter what border color it is.
I couldn't figure out when 7 works.
But usually don't enter the option. It will use the true plot's style.
Thanks, Snow
Dear Snow,
OK, I see that this syntax is for showing blocks or empty symbols. Right?
---
Andrey |
| snowli |
Posted - 08/13/2021 : 11:24:42 AM
It depends what plot type it is.
E.g. try to plot scatter plot with open circle, border and fill use different colors.
Though it's scatter plot, u can use the following to show blocks instead of circle shape in legend.
\l(1,4,1) it will show a block with border color of 4th point
\l(1,4,2) it will show a block with fill color of 4th point
Try to plot a bar chart with each bar using different border color, fill color and pattern colors.
U can use the following
\(1,4,1) to show block with border color of 4th point
\(1,4,2) to show block with fill color of 4th point
\(1,4,3) to show block with pattern color of 4th point
\(1,4,4) will show open circle with black color no matter what border color it is.
I couldn't figure out when 7 works.
But usually don't enter the option. It will use the true plot's style.
Thanks, Snow |
| AKazak |
Posted - 08/13/2021 : 10:48:48 AM
quote:
Originally posted by snowli
Hi Andrey,
Could you give an example of the need to set it?
If each point of your plot is different, u can right click legend and choose Point to Point legend which automatically shows each point in legend.
Thanks, Snow
Dear Snow,
Currently, I want to learn the way this syntax work.
Can you provide few examples since help page lack of them?
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Andrey |
| snowli |
Posted - 08/13/2021 : 09:21:11 AM
Hi Andrey,
Could you give an example of the need to set it?
If each point of your plot is different, u can right click legend and choose Point to Point legend which automatically shows each point in legend.
Thanks, Snow
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