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Clairekun
Germany
175 Posts |
 Posted - 10/01/2013 : 06:40:28 AM
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Origin Ver. and Service Release (Select Help-->About Origin): 9 SR2
Operating System: Windows 7
Hello, I would like to know if there's a script for what I need. I would need a script to open files (in the same folder) with similar file name into an XYYY table, for example:
ABC_1.asc
ABC_2.asc
DEF_1.asc
DEF_2.asc
DEF_3.asc
GHIa.asc
GHIb.asc
JKL.asc
So, I would like to have 4 different tables: ABC files, DEF files, GHI files and the JKL file, in XYYY format. Please note that not all of them have an underscore to separate them, although I believe I could change that if needed, but all of them do have the first 3 characters unchanged.
I would like to avoid, if possible, writing the names manually; I mean, the script would have to be something along the lines of "files with identical 3 starting characters should be in the same table"
I currently know how to open all files in a folder, both XY and XYYY format, I think I would only need a script to determine that bit about names.
Again, I do not know if such an specific script can exist.
Thank you and sorry for the long post. |
Edited by - Clairekun on 10/01/2013 06:41:01 AM |
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greg
USA
1378 Posts |
Posted - 10/01/2013 : 5:30:13 PM
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Maybe this will work the way you want?
dlgfile gr:=*.asc mu:=1;
loop(ii,1,fname.GetNumTokens(CRLF))
{
strFile$ = fname.GetToken(ii,CRLF)$;
strPart$ = strFile.GetFileName()$;
strPart$ = strPart.Left(3)$;
if(exist(%(strPart$))==2)
{
win -a %(strPart$);
newsheet;
impasc fname:=strFile$ options.FileStruct.NumericSeparator:=0 options.Names.FNameToBk:=0;
}
else
{
newbook name:=%(strPart$) option:=lsname;
impasc fname:=%(strFile$) options.FileStruct.NumericSeparator:=0 options.Names.FNameToBk:=0;
}
}
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New XYYY tables according to file name