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aeolian1
Germany
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 Posted - 06/06/2014 : 12:12:59 PM
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Origin Ver. and Service Release (Select Help-->About Origin): 9.0.0
Operating System:
Hello,
I attempted without success to use the "%c" method as described in http://www.originlab.de/www/support/resultstech.aspx?language=english&ID=101 to extract the values of a Bezier curve from a graph and place them in a worksheet, but was unsuccessful: the values in data2_b are just all the values of the data points, not the values of the Bezier curve through them. I realize that in a Bezier curve in Origin, the first point of every group of 3 is just the data point value, but the second and third points of each 3 in data2_b should be the Bezier curve values, and not the data point values. The tip in this link applies to version 7.5 - perhaps that is the problem. Is there a modification of this method that will allow it to work via Labtalk in version 9.0?
Thank you very much. |
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lkb0221
China
497 Posts |
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aeolian1
Germany
Posts |
Posted - 06/10/2014 : 09:11:18 AM
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Thank you, Zheng. Could you please clarify exactly how to implement this? Let's say I have a plot with the X column named "periodNum" and the Y column named "yoffsON", with the points connected by a Bezier curve. If I want to get the values of the Bezier curve at the X values contained in column X and put those values in a column named yoffsONi, I suppose I need to
1. Activate the plot window.
2. Run seomthing like the following code in the script window:
interp1 ix:=periodNum iy:=yoffsON oy:=yoffsONi method:=Bezier;
However, this code produces the error "Error: cannot find a (unique) variable corresponding to oy", instead of placing the values of the Bezier curve in the column yoffsONi. By the way, the column yoffsONi was previously created in the corresponding worksheet. Could you please tell me how to fix the code? Thank you.
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aeolian1
Germany
Posts |
Posted - 06/10/2014 : 11:08:18 AM
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P.S. I tried
win -a y0_ON_copy;
range Fitt=[FitR1]1!;
range iyx=%(Fitt)Col(1);
range iyy=%(Fitt)Col(3);
interp1 ix:=iyx iy:=iyy ox:=%(Fitt)Col(6) method:=Bezier;
Here, the XY data for interpolation is in X = Col(1), Y = Col(3), and the line connecting them on the plot is a Bezier curve. The above code produces a command error, and if I replace "Bezier" with "spline", it just puts the Col(3) values in Col(6) (instead of the spline values). So, the problem is still the same as in my original message.
More importantly, it seems that method:=Bezier is not allowed in interp1. The option "create Bezier data" is available on the plot, however, and that's what I'd like to do: just create the Bezier data. If interp1 can't handle Bezier curves, what command should I use? Thank you. |
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lkb0221
China
497 Posts |
Posted - 06/10/2014 : 4:30:40 PM
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Hi,
Well... Sorry I didn't notice that you are looking for a Bezier interpolate.
I'm sorry that there is no script access to generate this data, so the contact menu might be the only way.
Besides, the second and the third points are the "control points" of Bezier curve.
Zheng
OriginLab |
Edited by - lkb0221 on 06/10/2014 4:35:24 PM |
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aeolian1
Germany
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Posted - 06/11/2014 : 03:23:35 AM
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Thank you for your reply. I don't understand it completely:
1. What is the "contact menu", and how can I access it via Labtalk? I know that "menu commands" like "menu -e 57634" exist - can I use such a command to access the menu command "create Bezier data" that is available on the plot? If so, what is the specific command?
2. "Besides, the second and the third points are the "control points" of Bezier curve": could you please explain what you mean by this? I know that for a Bezier curve, the 1st, 4th, 7th, etc. points are just the data points themselves, but the 2nd, 3rd, 5th, 6th, etc. points should be the Bezier values that I am trying to access via Labtalk. |
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aeolian1
Germany
Posts |
Posted - 06/11/2014 : 04:48:23 AM
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I forgot my third question:
3. Could you please tell me what is wrong with the above code fragment when I use method:=spline?
I would really appreciate it if you could answer all three questions. Thank you! |
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aeolian1
Germany
Posts |
Posted - 06/11/2014 : 09:25:40 AM
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A P.S. to my question #1:
If I select "Create Bezier data" from the menu that I get if I right-click on the Bezier curve, I get a new worksheet that contains the Bezier data. This is the data I'm trying to access via Labtalk.
If I press Ctrl-Shift while selecting "Create Bezier data", I see "Menu id=38081" in the script window. The data points in the plot are "highlighted" (turn white), but no worksheet containing the Bezier data appears. If I run
menu -e 38081;
as a Labtalk command, the data points in the plot are again "highlighted", and again no worksheet containing the Bezier data appears. How can I get that worksheet to appear via a Labtalk command? Thank you. |
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lkb0221
China
497 Posts |
Posted - 06/11/2014 : 09:30:22 AM
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Hi,
1). Should be context menu, sorry it's a typo. Althrough we do have DoMenu marco, but there is no LT access to select the curve.
2). Our bezier curve is 3rd-order. So if you want higher, you need to calculate by yourself.
https://en.wikipedia.org/wiki/B%C3%A9zier_curve
3). Please see the interp1 page, there is no bezier option for method. "method:=spline" should work. Besides, you can use index number to indicate the options, like "method:=2".
Zheng
OriginLab |
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aeolian1
Germany
Posts |
Posted - 06/11/2014 : 09:41:13 AM
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Thank you for your response. I have two follow-up questions:
1. Can you please tell me exactly what is wrong with the code fragment
win -a y0_ON_copy;
range Fitt=[FitR1]1!;
range iyx=%(Fitt)Col(1);
range iyy=%(Fitt)Col(3);
interp1 ix:=iyx iy:=iyy ox:=%(Fitt)Col(6) method:=spline;
Here, the XY data for interpolation is in X = Col(1), Y = Col(3), and the line connecting them on the plot is a spline curve. This code just puts the Col(3) values in Col(6) (instead of the spline values that I want). So, the problem is still the same as in my original message.
2. About the "Create Bezier data" option from the context menu: can I somehow use "menu -e 38081" to do what I want (combined with some additional command)?
Thank you in advance for your answers to both questions. |
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lkb0221
China
497 Posts |
Posted - 06/11/2014 : 10:12:16 AM
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Hi,
Because spline will still pass all the points of your original data. interp1 is to find corresponding value of those points that are not in you original XY data but on the curve. Like "Find Y by X".
To higher the data density, you may use interp1xy X-function.
http://www.originlab.com/doc/X-Function/ref/interp1xy
There is no LT access to get that Bezier data, at least none as I can come up with. Yes, "DoMenu 38081" can return the workbook once the curve is selected, but you need to select it (click it one the graph) first to make to work, for that it's a context menu.
LT can only make a curve activated, but not selected.
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Accessing spline data