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 non-linear fit p value
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Ingridpz

2 Posts

Posted - 11/07/2016 :  11:21:32 AM  Show Profile  Edit Topic  Reply with Quote  View user's IP address  Delete Topic
Hi,

I've noticed that Origin does not provide the p value for non-linear curve fit. I read it is possible to calculate the P value by creating a script and running it in the After Fitting dialog box, however I don't know how to generate this script, can someone help me?
*I'm currently using the allometric 1 function.

Thanks a lot,

Ingrid

Shirley_GZ

China
Posts

Posted - 11/07/2016 :  10:06:04 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Hi Ingrid,


When you do fitting in Origin, Origin supports to output two kinds of p values,

Prob>|t| (Prob>|t| is a p-value for t-test, which is a probability with a value ranging from zero to one. )
and
Prob>F (Prob>F is a p-value for F-test, which is a probability with a value ranging from 0 to 1. )

See the help page below: http://www.originlab.com/doc/Origin-Help/NLFit-Algorithm

Which one are you talking about? Could you please give us more details?

Thanks,
Shirley


Originlab Technical Service Team
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Ingridpz

2 Posts

Posted - 11/08/2016 :  08:02:58 AM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Thanks Shirley for replying,

I had the following statistc results for my non-linear curve fit between the variables length of otoliths (CO) e total length of fish (CT):

PARAMETERS
CO (mm)
Number of Points 44
Degrees of Freedom 42
Reduced Chi-Sqr 0,02424
Residual Sum of Squares 1,01829
R-Square(COD) 0,94743
Adj. R-Square 0,94618
Fit Status Succeeded(100)


STATISTICS
Value Standard Error t-Value Prob>|t| Dependency
CO (mm) a 0,01341 0,00301 4,45839 6,04685E-5 0,99453
CO (mm) b 1,13431 0,05225 21,71126 0 0,99453

SUMARY

a b Statistics
Value SE Value SE Reduced Chi-Sqr Adj.R-Square
CO (mm) 0,01341 0,00301 1,13431 0,05225 0,02424 0,94618


ANOVA TABLE
DF Sum of Squares MeanSquare Fvalue Prob>F
CO (mm) Regression 2 88,17878 44,08939 1818,49 0
CO (mm) Residual 42 1,01829 0,02424
CO (mm) Uncorrected Total 44 89,19707
CO (mm) Corrected Total 43 19,37039

Both p values(t and F tests)are equal to 0. I think this is quite odd..does that mean that the p value is actually 0 or what?

Thanks again,
Ingrid
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