The standard expression is dB = 20*log(amplitude/reference). If you choose a reference amplitude of 1 then you can enter the expression 20*log(col(r)) in the Set Column Values dialog for column r.
Are you sure 20*log(col(r)) is right? because that gives me an insertion loss of about 100dB for my filter, which is just wrong... (hopefully!!). Do i have to normalise col(r) first?
Yes, that expression assumes a reference amplitude, or normalization factor, of 1. If you know the reference level use 20*log(col(r)/ref). If the col(r) values represent Vout then ref=Vin.
...You might also need to take into account any normalization done by the FFT operation. I don't remember exactly what Origin does, but FFT values are typically multiplied or divided by N or sqrt(N), where N is number of points.