I was using single exponential equation y= A0 + A1*(1-exp(tau1*x)) to do the curve fitting. I got the result like:
Tau = 0.02639 error3 = 3.41E-14
Error3 is the error for Tau. Now I need to get the inverse of the Tau: k = 1/Tau. How to get the error of k? I tried to use error3/Tau^2 as the error of k. Is this correct?
However, from a propagation of errors viewpoint... http://en.wikipedia.org/wiki/Propagated_error ...the error of k is indeed equal to error3/tau^2. Of course you can test that yourself merely by defining another version of your function with k rather than tau1. I find it true with the simpler ExpDec1 function.