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 Problem about curve fitting from a new user
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mingkeng

China
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Posted - 10/09/2007 :  04:46:52 AM  Show Profile  Edit Topic  Reply with Quote  View user's IP address  Delete Topic
Origin Version (Select Help-->About Origin): OriginPro 7.5
Operating System: XP sp2

I am a new user of using the curve fitting. I have a sort of number:

x | y
-10 | 0.3942
-5 | 0.3912
0 | 0.3869
5 | 0.3759
10 | 0.3454
15 | 0.3149
20 | 0.3066
25 | 0.3022
30 | 0.2993

I want to fit the number into the function as follows

y=d0+d1*tanh[d2*(x-d3)]

d0d1d2d3 are the parameters.

I use the fitting wizard, but I cannot find the Hyperbolic Tangent function. What shall I do?

Help please, thanks!

Edited by - mingkeng on 10/09/2007 07:24:33 AM

Edited by - mingkeng on 10/09/2007 07:25:37 AM

Fay_Guo

China
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Posted - 10/09/2007 :  9:50:36 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Hi,
Could you try to use Advanced Fitting Tools? From that you can define the functions as what you want.
In addition, I'm sorry to tell you that your definition should be defined as
y=d0+d1*tanh(d2*(x-d3))



Thanks
Fay
OriginLab Technical Service
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mingkeng

China
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Posted - 10/10/2007 :  9:02:24 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Thanks for your help!
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casadyb

USA
1 Posts

Posted - 11/06/2014 :  3:42:00 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Hi mingkeng,

I am just delving into fitting the hyperbolic function to a set of data - however, this is the first instance of the formula I have found with the necessary parameters (intercept, slope and inflection point, namely).

From this formula: y=d0+d1*tanh(d2*(x-d3))can you tell me what the parameters are? For example, with some test data it looks like d3 is the point of subjective equality (when y=.5).

I greatly appreciate your help!
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greg

USA
1378 Posts

Posted - 11/07/2014 :  10:12:53 AM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
I don't know the technical names (which probably vary with industry or discipline), but I would refer to them as:
Inflection Point Y (d0), Magnitude (d1), Shape Factor (d2), Inflection Point X (d3)
So the resultant curve would have a minimum value of d0 - d1 and a maximum of d0 + d1 and have an inflection point ( derivative slope = 0 ) at (d3, d0).
As d2 decreases from about 0.5, the transition becomes more gradual; as d2 increases from about 0.5, the transition becomes sharper.
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