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iggboert
Germany
7 Posts |
 Posted - 11/17/2009 : 07:51:44 AM
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Origin Ver. 8 and Service Release SR4:
Operating System: WinXP
Hello,
to delete some selected data of a worksheet i used this:
wxt "col(4)[i]<0.001" sel:=1;
menu -e 36442;
but now i want to make the code more efficient because i have tons of data.
Now i'm using datasets to calculate and for analysis. i wanted to use the following code to erase the nonnecessary data. But it doesnt work on a dataset, only on a worksheet. Any suggestions?
dataset temp1 = {1,2,3,4,5,6,7,8,9,0};
for(i=10,i=0,i--)
{
if(temp1[i]<=5||temp1[i]>=3)
{
mark -d temp1 -b i -e i;
// tried also "mark -d temp1[i]"
};
};
Regards
Christoph
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easwar
USA
1964 Posts |
Posted - 11/19/2009 : 09:28:46 AM
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Hi Christoph,
Sorry for the late response, we do not have a method in LT to delete elements in a temp dataset, thanks for the suggestion, we will add this in a future service release/version.
For now methods exist in Origin C for deleting elements of a vector etc, so you may want to consider using Origin C
Easwar
OriginLab
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greg
USA
1378 Posts |
Posted - 03/22/2010 : 5:06:06 PM
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We have added the RemoveAt method to remove elements of a loose dataset based on index. You can now use:
dataset temp1 = {1,2,3,4,5,6,7,8,9,0};
temp1.removeat(9); // Removes '9'
temp1.removeat(7); // Removes '7'
temp1.removeat(5); // Removes '5'
temp1.removeat(3); // Removes '3'
temp1.removeat(1); // Removes '1'
col(1)=temp1; // Now equals (2,4,6,8,0}
dataset temp1 = {1,2,3,4,5,6,7,8,9,0};
temp1.removeat(1); // Removes '1'
temp1.removeat(3); // Removes '4'
temp1.removeat(5); // Removes '7'
temp1.removeat(7); // Removes '0'
temp1.removeat(9); // Does nothing - index out of bounds
col(2)=temp1; // Now equals {2,3,5,6,8,9}
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deleting values from dataset (not worksheet)