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 behavior of datatype UINT		  New Topic  Reply to Topic
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TreeNode

64 Posts
Posted - 03/22/2010 :  06:41:27 AM  Show Profile  Edit Topic  Reply with Quote  View user's IP address  Delete Topic
Origin Ver.8 SR6:
Operating System: XP

Hi,

using datatype UINT behaves not in the way I would expect.

void integer_data_types_ex1()
{
	int iNum;
	
	UINT uiNum;
	USHORT usNum;
	
	iNum = -5;
	uiNum = (UINT)iNum;		// value stays the same
	usNum = (USHORT)iNum;	
	
	printf("unsigned integer: %d\n", uiNum);	// -5
	printf("unsigned short: %d\n", usNum);		// 65531
}


|-- TreeNode
...|-- a??
...|-- ha!!

greg

USA
1378 Posts
Posted - 03/23/2010 :  3:38:09 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Do not confuse printf options with how a value is internally handled.
The %d option means to treat the value as a signed decimal.

Try these lines:

// this outputs 4294967291 which is 2^32 - 5
printf("unsigned integer: %u\n", uiNum);
// this outputs 65531 which is 2^16 - 5
printf("unsigned short: %u\n", usNum);
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TreeNode

64 Posts
Posted - 03/23/2010 :  8:26:20 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Sorry, my fault...

thank you very much for your advice!

|-- TreeNode
...|-- a??
...|-- ha!!
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