If anyone can help me ( as I am a physicist, not a programmer), I will be most appreciative. Also, if anyone can help me get started, I would also be most appreciative.

Data1_b = Data1_b - lr.a, for example, subtracts the value of the intercept of the last linear regression from Data1_b and puts the results back in Data1_b.

While your request doesn't require a great deal of LabTalk^TM skill, non-programmers and busy professionals might wish to make use of our consulting services to create custom routines. Visit the Services Available area to get more details.

[This message has been edited by rtoomey (edited 08-10-99).]

win -n plot

//create a graph window

layer.plotxy(Data1_A, Data1_B)

//plot column A of my dataset as X and column B of my dataset as Y

lr Data1

// Do a linear regression of the graph (ie a linear fit of the data points)

type "The Dark Current is " lr.b

// I want to output the slope of the first graph and tell that that is what the value of the dark current is

Data1_D = Data1_A - lr.a

// I want to make a new column in my dataset and sore the value in it of Column one minus the intercept of the first graph. Question? Would it be better if I just wrote over my original column A?

win -n plot

// Open a new graph window

layer.plotxy(Data1_D, Data1_C)

//plot column D of my dataset as X and column C of my dataset as Y

lr Data1

//Do a new linear regression of these points

type "The Responsivity is" lr.b;

// output that the responsivity of the data is the slope of the second graph

type "The noise is" sqrt(lr.a)/lr.b;

// Output that the noise of the date is the square root of the intercept of the second graph divided by the slope of the second graph.

That is it I suppose. I guess I am really more lost than ever, so any help would definately ake my day.