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Mike Buess

USA
3037 Posts
Posted - 07/05/2002 :  10:54:50 AM  Show Profile  Edit Topic  Reply with Quote  View user's IP address  Delete Topic
The normal method for accessing the nnth line of a string variable is

%A=%[%Z,@nn];

But that expression only works for nn<=100, evven though you can fill %Z with many more than 100 lines.

Example...

%Z=line 1;
loop (ii,2,200) {
%Z=%Z
line $(ii);
};
%Z=;
line 1
line 2
.
.
.
line 200

%A=%[%Z,@100];
%A=;
line 100
%A=%[%Z,@101];
%A=;
(no return value)

Is there another LabTalk or OriginC method for access the lines > 100?

Mike Buess
Origin WebRing Member

Edited by - Mike Buess on 07/05/2002 10:56:04

Edited by - Mike Buess on 07/05/2002 11:07:19

cpyang

USA
1406 Posts
Posted - 07/05/2002 :  1:07:58 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Best would be if we add a new method to string class to handle lines. For now, the following code will show how you can do this.


void tt()
{
	GraphLayer gl = Project.ActiveLayer();
	if(NULL==gl)
		return;
	
	GraphObject	gr;	
	gr = gl.GraphObjects("Text");
	if(NULL==gr)
		return;
	
	string str = gr.Text;
	// assume text does not have '|' so
	// can be used as separator
	str.Replace("\r\n","|");
	StringArray sa;
	int nCount;
	if((nCount = str.GetTokens(sa, '|')) > 0)
	{
		for(int ii = 0; ii < nCount; ii++)
			out_str(sa[ii]);
	}
	return;
}




Edited by - cpyang on 07/05/2002 13:08:37
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Mike Buess

USA
3037 Posts
Posted - 07/05/2002 :  2:00:04 PM  Show Profile  Edit Reply  Reply with Quote  View user's IP address  Delete Reply
Good idea. Actually, I can probably just create %Z as one line with '|' separators in the first place.

Thanks,

Mike Buess
Origin WebRing Member
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